✨ Best Answer ✨
∆ADF=∆ABE (SAS全等)
因此，DF:DC= EB:BC （DC=BC)
然後利用相似三角形∆EBG&∆ECF 可得EB:BC=EG:GF 由此可推的DF:FC=EG:GF
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✨ Best Answer ✨
∆ADF=∆ABE (SAS全等)
因此，DF:DC= EB:BC （DC=BC)
然後利用相似三角形∆EBG&∆ECF 可得EB:BC=EG:GF 由此可推的DF:FC=EG:GF
Users viewing this question
are also looking at these questions 😉
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