Mathematics
Senior High
Resolved
回答のように a+b+c=A、b+ … と書くべきですか?? 1枚目の写真のように、文字に置き換えずに計算しても良いですか??
16
24 次の式を計算せよ。
(a+b+c)²-(b+c-a)²+(c+a−b)²-(a+b-c)²
>
= (a+b+c+b+c-a) (a+b+c-b-c+a) + (cta-b ta+b-c) (c +α-b-a-b+c
= (2b+2c92a + 2a(-2b+2c)
4ab+4ac-4ab + 4ac
Sac
13
/\/\/
3
3
1
- d)}
*
(c+a−b)² = {a-(b-c)}²
=a²-2(b-c)a+(b-c)²
(a+b-c)² = { a+(b—c)}²
=a²+2b-c)a+(b-c)² 4
① -② +③ - ④ から
5x=4(b+c)a-4(b-c)a= 8ac
[a+b+c=A, b+c=a=B, c+a-b=C,
a+b c = D とすると
¹jxt=(A²-B²)+(C² — D²)
=(A+BXA-B)+(C+DXC-D)
=(26+2c)-2a+2a(-2b+2c)
= 8ac
25 (1) = x³ +3.x².3+3•x-3² +3³
例1
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わかりましたー!!ありがとうございます( *´﹀`* )