Mathematics
Senior High
Solved
(3)の問題なのですが最後どのような計算したら(√2)nになるのですか?
4 次の等比数列{an}の一般項を求
(1) * 1,4,16,64,
(3)* √2, 2, 2√2, 4,
(3) この等比数列の公比をrとすると
2
found
2
a2
r ==
an
=√2
初項√2,公比√2の等比数列の一般
90
項は
an=√2・(√2)=(√2)"
Answers
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉
