Mathematics
Senior High
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こちらの問題の式をもう少し細かく式にしてほしいです‼️
n
n
(5) (k+1)(k-2)=(k2-k-2)
k=1
k=1
n
n
=k²-k-2
k=1
k=1
k=1
=
= n(n+1)(2n+1)-n(n+1)−2n
= n(n+1)(2n+1)-3(n+1)−12}
S
= n(2n²-14)= n(n²-7)
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あと、2行目→3行目は、Σの公式なのですがそれはわかりますか?