Mathematics
Senior High
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1 次の和を求めよ。
(1) Σ(2k-7)
12
k=1
n
(4) k(k+1)
k=1
n
(2) (5k²-4k+2)
Σ
k=1
(5)
n
m=1
(3m-1)²
(3) Ż(4k³-1)
k=1
n
(6) (3+2)
k=1
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