Mathematics
Senior High
2^x＝7⇔x＝log(↓2)7
このように対数を用いる解き方は代数的な解き方と言えますでしょうか？またlog(↓2)7は超越数ですか？
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2^x＝7⇔x＝log(↓2)7
このように対数を用いる解き方は代数的な解き方と言えますでしょうか？またlog(↓2)7は超越数ですか？
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