Mathematics
Junior High
(1)と(3)の解き方もう少しわかりやすく教えてください🙏🏻🙏🏻
(1) (√2-1)(√2+2)
=(√2)²+(−1+2)√2+(-1)×2
=2+√2-2
=√2
(2) (2-√3)²52
= 2²-2x√√√3x2+(√3)²
=4-4√3+3)
=7-4√3******0
して、正
BADE
(大阪)
=3+4√3-5+2√3
=-2+6√/3
(滋賀)
(3) (√3+5)(√3-1)+√12
=(V3)2+(5−1)/3+5X(−1)+2,3
2-
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