✨ Best Answer ✨
-sinθ+cosθ
=√2{(-1/√2)sinθ+(1/√2)cosθ}
=√2{cos(3π/4)sinθ+sin(3π/4)cosθ}
=√2sin(θ+3π/4)
です。
(2)教えてください!!
✨ Best Answer ✨
-sinθ+cosθ
=√2{(-1/√2)sinθ+(1/√2)cosθ}
=√2{cos(3π/4)sinθ+sin(3π/4)cosθ}
=√2sin(θ+3π/4)
です。
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