Mathematics
Senior High
(3)で7/6πと19/6πがどこから出てきたのかわかりません。教えてください🙏
447
Xal
*(3) cos(20+) ≤-
sin(0+1)</2 *(2) tan(0
6
√√3
2
tan(6->1
3
(3) 20+1=α とおくと
4
cosa ≤-
—
5
√3
6
5/₁
2
π
4
0≦0<2πから
すなわち Sa 1/27
T
-T
②の範囲で, ① を解くと
(20)
1
≤20+<4T+7
2
sas/T, sas
T30
7
11 31
2"SOS 24", 24
≤
-π,
24
19 20 S
6
-T
すなわち
0
T 7
5 R≤ 20+ ≤ 1/2, 1/7 R≤ 20+1 ≤ 10 / ₂
19
6 T
4-6, 6
6'
T
6 fe
よって
aiz 35
T≤0 ≤ 24
T
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