Mathematics
Senior High
Resolved
3行目から4行目になるのがわからないです！
2
sin0=√1-cos² (>0) 35
COS
12 | AB || AC | sin
0
2
= |AB|| AČ | √1 - cos 0
= √ | AB || AC |-|(|AB|| AČ | COS 0)ª
2
==√|AB|| AC|-(AB· AC)"
2
2
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