✨ Best Answer ✨
𝒙²-𝒚²=(𝒙+𝒚)(𝒙-𝒚)より
{(1+√5)/√2+(1-√5)/√2}{(1+√5)/√2-(1-√5)/√2}
=(2/√2)(2√5/√2)=4√5/2=2√5
だと思います
途中式(解き方)を教えてください。
1枚目問題で2枚目が答えです。
✨ Best Answer ✨
𝒙²-𝒚²=(𝒙+𝒚)(𝒙-𝒚)より
{(1+√5)/√2+(1-√5)/√2}{(1+√5)/√2-(1-√5)/√2}
=(2/√2)(2√5/√2)=4√5/2=2√5
だと思います
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