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1/3k(k+1)(k+2)+(k+1){(k+1)+1}

中カッコの中を外して、後ろの項の係数1を3/3にかえる
=1/3k(k+1)(k+2)+3/3(k+1)(k+2)

因数でまとめる
=1/3(k+1)(k+2)・k + 1/3(k+1)(k+2)・3
=1/3(k+1)(k+2)・(k+3)

となりました

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1/3×k(k+1)(k+2)+(k+1)((k+1)+1)
=1/3×k(k+1)(k+2)+(k+1)(k+2)
=1/3×k(k+1)(k+2)+1/3×3×(k+1)(k+2)
=1/3×(k(k+1)(k+2)+3(k+1)(k+2))
=1/3×(k+3)(k+1)(k+2)

BaSO4

=1/3×(k+3)(k+1)(k+2)

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