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x²+3x-10=0なら
足して+3、掛けて-10となる2数+5と-2を見つけて
(x+5)(x-2)=0とするのと同様に
x²+ax-2(a+2)=0なら
足してa、掛けて-2(a+2)となる2数を探します
-2とa+2なので
(x-2)(x+(a+2))=0です
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![(2)[1]の式はなぜこうなるのでしょうか？
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