Mathematics
Senior High
Solved
二段目から三段目にかけてわかりません
(4) (a+b+c)(ab+bc+ca)-abc
={a+(b+c)}{(b+c)a+bc}-bca
=(b+c)a²+bca+(b+c)²a+bc(b+c)-bca
=(b+c)a²+(b+c)²a+bc(b+c)
=(b+c){a²+(b+c)a+bc}
=(b+c)(a+b)(a+c)=(a+b)(b+c)(c+a)
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