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x^4 = (x^2)^2，81=(3^2)^2
(x^2)^2 - (3^2)^2
= (x^2+3^2)(x^2-3^2)
= (x^2+9)(x^2-9)
= (x^2+9)(x+3)(x-3)
故 p+q+r=9
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x^4 = (x^2)^2，81=(3^2)^2
(x^2)^2 - (3^2)^2
= (x^2+3^2)(x^2-3^2)
= (x^2+9)(x^2-9)
= (x^2+9)(x+3)(x-3)
故 p+q+r=9
謝謝
Users viewing this question
are also looking at these questions 😉
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