Mathematics
Senior High
Resolved
この問題なのですが、何回計算し直しても21/40、7/40のようになりません。計算過程が知りたいです。教えてくださるとうれしいです🙇🙇
P(X = 1) =
P(X = 2) =
=
3C1.7C2
10 C3
3C₁₂+7C₁
10 C3
21
=
40
7
=
40
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