Answers

✨ Best Answer ✨

詳見附圖
已知∠B=58˚且線段AD//線段BC,所以∠BAD=122˚
連接OA、OB、OC,
因線段AD為切線,所以線段OA⊥線段AD,可得∠BAO=32˚
又△ABO中,線段OA=線段OB,所以∠ABO=32˚,可得∠OBC=26˚,
又△OBC中,線段OB=線段OC,所以∠OCB=26˚,∠BOC=128˚=BC弧

Post A Comment
Were you able to resolve your confusion?