[log(1+x)] (0〜t)つまりlog(1+t)-log1 = log(1+t)
と同じように、
[log(1+t)] (0〜t)もlog(1+t)です
変数がxなら、(xにtを代入したもの)-(xに0を代入したもの)です
変数がtでも、(tにtを代入したもの)-(tに0を代入したもの)です
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