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式の計算
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(2sin0+ 3cos0)2 + (3sin0-2cos0)2

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✨ Best Answer ✨

(2sinθ + 3cosθ)² + (3sinθ - 2cosθ)²
= (4sin²θ + 12sinθcosθ + 9cos²θ) + (9sin²θ - 12sinθcosθ + 4cos²θ)
= 13(sin²θ + cos²θ)
= 13 (答)

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普通のxとyの文字式と同じように展開してsin^2θ+cos^2θ=1の公式を使えば解けるかな

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