✨ Best Answer ✨
|x−1|+|x−2|
−2x+3(x<1)・・・①
1(1≦x≦2)・・・②
2x−3(2<x)・・・③
①〜③それぞれ−x^2+2x+2と連立。
①
−x^2+2x+2＝−2x+3
x＝2±√3
②−x^2+2x+2＝1
x＝1±√2
③−x^2+2x+2＝2x−3
x＝±√5
xの全範囲が解だから
2−√3<x<√5
イメージできるならこのやり方もありかも？
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それです!!これです!!ありがとうございました!!