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√7の小数部分a=√7-2 (2<√7<3より)
a²+2a=(√7-2)²+2(√7-2)
=7-4√7+4+2√7-4
=-2√7+7
ではないでしょうか？
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√7の小数部分a=√7-2 (2<√7<3より)
a²+2a=(√7-2)²+2(√7-2)
=7-4√7+4+2√7-4
=-2√7+7
ではないでしょうか？
Users viewing this question
are also looking at these questions 😉
