(x+y)(x-y)(x^2-xy+y^2)(x^2+xy+y^2)
={(x+y)(x^2-xy+y^2)}{(x-y)(x^2+xy+y^2)}
=(x^3+y^3)(x^3-y^3)
=x^3+3 － y^3+3
=x^6-y^6
問題文が展開せよでしたらこうなります！
Answers
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉
Recommended
詳説【数学Ⅰ】第一章 数と式～整式・実数・不等式～
8996
117
詳説【数学Ⅰ】第二章 ２次関数（後半）～最大・最小・不等式～
6136
25
詳説【数学Ａ】第１章 個数の処理（集合・場合の数・順列組合）
6118
51
詳説【数学Ａ】第２章 確率
5865
24
ありがとうございます！
理解できました♡♡