Mathematics
Senior High
どのようにこの変形した式から焦点と準線が分かるんですか？
種六2*2+3yx+4y+5=0の表す放物線の焦
点の座標、準線の方程式を求めよ。
2y^2+3x+4y+5=0
2(y+1)^2+3x+3=0
(x+1)=(-273)(y+^2
焦点の座標
(-1178.-1)
準線の方程式
x=-5/8
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