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∠CAD=1/2 ∠COD = 55°
なので、∠ADC=75°
向かい合う角の和は180°となるので、
∠CBA=180-∠ADC=105°
この長さの比より、
∠BCA = 2 ∠BAC = 2x
三角形の内角の和が180°より、
105+2x+x =180
x=25° かな
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