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計算の順番が違うからです。
まず足し算より掛け算が先に計算します。

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ありがとうございます!

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1/6n(n+1)(2n+1)−4n
=1/6n[(n+1)(2n+1)−24]
=1/6n[(2nの2乗+3n+1)−24]
=1/6n(2・nの2乗+3n−23)

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