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定義に沿って計算すればよいです
J＝|∂x/∂r ∂x/∂θ|
|∂y/∂r ∂y/∂θ|
＝|acosθ -arsinθ|
| bsinθ brcosθ|
＝abr
Mathematics
Undergraduate
Resolved
重積分の極座標変換でのヤコビアンの求め方がイマイチわかりません。何でこの問題のヤコビアンはabrなんでしょうか？
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(⑳*朗還 G7'COS 9, =がsinの
この変換のヤコビアンは廊ヨに:
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