Answers
(x+y-z)(x-y+z)
={x+(y-z)} {x-(y-z)}
y-zをMと置いて、
=(x+M)(x-M)
=x^2-M^2
M=y-zを代入して
=x^2-(y-z)^2
あとこれを解けばできるはずです!
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉
Recommended
詳説【数学Ⅰ】第一章 数と式~整式・実数・不等式~
8999
117
詳説【数学Ⅰ】第二章 2次関数(後半)~最大・最小・不等式~
6137
25
数学ⅠA公式集
5748
20
詳説【数学A】第3章 平面図形
3626
16