✨ Best Answer ✨
[log|x＋√(1＋x²)]‛
＝[1/{x＋√(1＋x²)}]・{x＋√(1＋x²)}‛
＝[1/{x＋√(1＋x²)}]・[{x＋√(1＋x²)}/√(1＋x²)]
＝1/√(1＋x²)
Answers
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉
✨ Best Answer ✨
[log|x＋√(1＋x²)]‛
＝[1/{x＋√(1＋x²)}]・{x＋√(1＋x²)}‛
＝[1/{x＋√(1＋x²)}]・[{x＋√(1＋x²)}/√(1＋x²)]
＝1/√(1＋x²)
Users viewing this question
are also looking at these questions 😉
