(3) AEBF = AABF
= 2√5 x
×
3
8
ADAE ABFE
AEBF = ADBC X
EF
AF
=
3√5
4
, DEBE = 5:3 1
BEDA
より
BF
X
BC BD
ADBC = AEBF X
BC
X
BF BE
15
BD-3√5 × × $10/5
=
X
=
4
3
10√5
ABB
EFCD = ADBC - AEBF
ST:2,53a5T
5
IAE
=
13
10√5 a
12
5
3
10/53/531/5
3√5 31√5
TOTA
4
DATAN
3③
F
-HO
解答
'C
31 5
12