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化学 高校生

電池についての問題です!解答の赤の部分がなぜこのように引いたり足したりするのかがよく理解できません💦よろしくお願いします🙇‍♀️

] 13 質量パーセント濃度が 35.0%の希硫酸 520g を用いて (1)25) ★★ 鉛蓄電池を作製し, 放電させたところ, 0.25molの電 (2) 4.5 子が流れた。 この放電によって, 電解液中のH2SO4 は(3)32 放電前に比べて1 ★★ g減少し, H2O は 2 ** 増加するので,希硫酸の質量パーセント濃度は 3★★ % (すべて2ケタ) となる。 H = 1.0, 0 = 16, S = 32, Pb =207 (関西) 解き方 鉛蓄電池の放電時における全体の反応式lom e 2mol Pb + PbO2 + 2H2SO4 → 2PbSO4 + 2H2O から, e が 2mol 流れると H2SO4 (分子量 98) が 2mol 減少し, H2O(分子 量18)が 2mol 増加するので,e-が 0.25mol 流れると, (2) Pb- 1+2H Jovem (e-) (H2SO4) TO ST 2mol 2mol s #ALOd¶ - 0.25mol 0.25mol PERINTEE となる。 よって, 電解液中のH2SO4は, 0.25mol 減少した H2SO4 [mol] × ≒ 32〔%〕 となる。 JIRES 溶質 〔g〕 : 520× 溶液〔g〕 : 520 × - 98g 1mol 減少し, H2O は, 0.25mol 増加した H2O [mol] 増加した H2O [g] 増加するので,希硫酸の質量パーセント濃度は, THEOR 18g Imol ESTUD 減少した H2SO4[g] 35.0 100 CO6829 0209 (H2O) STU + 2mol_ 02&st Joan & + 0.25mol = 24.5 〔g〕 = 25 〔g〕 [lom) H2SO4 24.5 = = 4.5 〔g〕 Tom 09.0 124.5」 + 4.5g H2SO4 H₂O x 100 03 655SPOWORS JU H 3 「マンガン酸 *** 12枚 質の 「アルカリマ 代正 M

解決済み 回答数: 1
化学 高校生

本文にジエチルエーテルには不溶と書いてありますが、なんのためにこの記述がしてあるのですか? 変なこと聞いてすいません。なぜここでいきなりジエチルエーテルが出てくるのか分かりせん、

A図3 アルコールの用途と構造式 不凍液は誤飲防止のため,着色されている。"c"^てilてRI 01.2-エタンジオール エチレングリコールとも呼ばれる。無色で粘性 1,2-ethanediol ethylene glycol のある不揮発性の液体で,吸湿性がある。水と任意の割合で溶け合うが, ジエチルエーテルには不溶で,有毒である。自動車エンジン冷却用の不凍 液や,プラスチックの原料などとして用いられている。 | 01,2,3-プロパントリオール グリセリンとも呼ばれる。無色で粘性の 1,2,3-propanetriol glycerine 15 ある不揮発性の液体で, 吸湿性がある。水と任意の割合で溶け合うが, ジ ゆし→p.350 エチルエーテルには不溶である。油脂の加水分解で得られる。甘味があり 無毒なので,食品, 医薬品, 化粧品の成分として広く用いられる。また, ブラスチックや火薬(ニトログリセリン)などの原料としても使われる。 nitroglycerin 不凍液 化粧品 19 小さい H H H H H T T H-C-C-H H-C-C-C-H OH OH OH OH OH 3 1,2,3-プロパントリオール (グリセリン) 20 1,2-エタンジオール (エチレングリコール) し。 "Ca 0空気を遮断」 て田4

解決済み 回答数: 1
化学 高校生

【英語ですみません】最後の12番は何を書いたら良いのでしょうか…? Video C の実験では、aqueous solution にlead(ii) nitrate, aqueous solution にPottasium iodide を入れていました。 2KI (aq)... 続きを読む

With lead (I) nitrate solution. This precipitation reaction produces a bright yellow solid. (point values in parentheses) Part 1: 1. Copy the unbalanced reaction below into your lab notebook. Balance the reaction by adding coefficients. (1) KI (aq) Pb(NO,), (aq) KNO, (aq) Pbl, (s) 2. a) Which trial are you assigned? b) Copy the data table below into your notebook. Watch video A (make sure it's the correct trial!) and collect your data. You may need to pause or rewatch the video, it goes quickly. (1.5) Mass of Empty Beaker (g) Mass of Beaker+ solid Pb(NO,)。(g) Volume of 1.0 M KI (aq) (mL) For the following calculations, show all your work for full credit. 3. What mass of solid Pb(N0,), was added to the beaker? (1) 4. If the solid Pb(NO,), was dissolved in 45 mL of water, what is the molarity of the Pb(NO,)。 solution? (2.5) 5. Which compound is the limiting reactant? (4) 6. What mass of lead (II) iodide (PbL,) should be produced? (2) Part 2: 7. Watch video B (make sure it's the correct trial!) to see the complete reaction and collection of the product. Copy the data table below and record your data. (1) Mass of filter paper (g) Mass of filter paper + dried precipitate (g) 8. What mass of precipitate was collected? Show your work. (1) Calculate the percent yield for the reaction. Show your work. (2) 10. For your trial, which three ions were present in the filtered solution at the end of the reaction? In other words, which three ions are still dissolved at the end of the reaction? Defend/explain your 9. answer. (3) 11. Watch video C - watch both tests for your trial and record your observations. (1) a) Add lead (II) nitrate - b) Add potassium iodide - 12. These tests were conducted to prove the identity of the limiting reactant. Considering your answers to the previous two questions, describe how these tests support the prediction you made in question 5 about which compound is the limiting reactant. (2)

解決済み 回答数: 1
化学 高校生

RHEED法の原理と得られる7つの情報が、この英文に書かれているみたいなのですが、よく分かりません。 分かる方助けてください!🙇‍♂️

INTRODUCTION Reection high-energy electron diHiraction (RHEED) uses a Rnely collimated electron beam with energy of 10-100 keV. The beam irradiates a sample surface with gazing incidence to obtain forward scattered difraction patterms. RHEED enables us to analyze structures of crystal surfaces at atomic levels and also to in situ monitor growth processes of thin films (mo、1988: Ichimiya and Cohen、2004: Peng et al.. 2011). From the arrangement。intensity and profile of the dilraction spots in RHEED patterns as described below in detail、 one can obtain various kinds of information: (1) the periodicity (unit cells) in atomic arrangements. (2) flat- ness of surfaces. (3) sizes of grains/domains of surface structures and microcrystals grown on the surface. (3) epitaxial relation between the grown flms/islands with respect to the substrate. (5) parameters character- izing structural phase transitions. (6) individual atomic positions in the unit cells. and (7) growth styles of thin films and numbers of atomic layers grown. The most important advantages of the method are that it is quite easy to install the RHEED apparatus in Yarious types of vacuum chambers without interfering with other components of apparatuses and to do real- time monitoring during thin-Rlm growths. Because of these advantages.RHEED is nowwidelyusednotonlyin research Iabs of surfaces and thin fims. but also in device production processes in industry Low-energy electron diiraction (LEED、see article Low-ENNERcy ErecroN DirscmoN)。 in which an electron beam of 10-100 eV in energy is irradiated onto a sample surface with nearly normal incidence to obtain back- scattered difraction patterns. is also widely used to analyze the atomic structures of crystal surfaces. Since one has to make the sample face directly to the LEED

未解決 回答数: 1
化学 高校生

解き方が分かる方、お願いします。m(_ _)m

EEモキモキギキモEi hese atoms were formed in the firstfew secods afler the Big Bang th event that marked | LegHmpimeoftheuniverwe HHowewcr thereisgttle free hydrogenon Fartb becausc Hmolecule mgYem hh moeat ueh high merge speeds at mey exape fom the Erths rmeYitr Most of the Earthis hydrogen is preeent as water either im the oceans or trappcd imside minerily ) mdclays Hydrogenisalsofoundimthehydrocarbons*! that make up thefossilfuelscoaL[ ん md naturml gas ILiaksenergytorelesee om these compounds Ifwe yaptto we SS a fel we must produce the gas using lcss energy than it generates when bumed. Beceuse water sits only combuston*3 prodoct_ hydrogen bnrms without poluting the ai Cr onibuitng signifcantly to the grecnhouse cfect*3 Coal[ A ] and natural gaN ae becoming increasingiy rare.but there isenough waterin the oceans to gencrate the hydrogen fuel we shall cver need. Hydrogen is obtaincd from water by elecrolysis** but that prOceSt requires electricity that has been gencrated esewhere。 Chemists are currently Seeing as Of using sunlight to drive the water-spitting reaction.the "decomposieon*" of ater eiemen Waterspbtting reacton : 2HzO(ianid) 一 2Hz(eas) Oz(gssy At present most commercial hydrogen is obtagted ss a byproduct*fof[ A ]refmmgYPma Sequence of two catalyzed reactons*9。 The gst is a reiorming reacton*io in which a jjdrocarbon and esm sre cnnweried into cartbon monoxide*! and hydrogen ovcr a nickl catalystYP: 。keforning reaction : CH(gss) +HkO(gas) 一 CO(gay) +3H(gy) The miiture ofproducts caled synthess gas "js the staring point for manufacture of many dher ompounds inciuding 。methanol Tbe reforming reacton is folowed by the shif reaction*1 im which the carbon monoxide in the synthesis gas reacts with more Water Shi reacion : CO(gms) +HLO(gas) 一 CO:(m) +Hktgs) Hydrogen is lso prepared pn smal amoupts. ja he laboratory by reducing hydrogen ions from strong acid with a metal (て Ama aaaL Janeu Chenical Prmepke: The Qwex cr msght 001 W.了Feman をCo から一 更して引有8) 1、 hydrocarbon : 庶化水素 2.combuston : 朱 3. greenhouse cert:温宅効果 4 Jayai : 電気分狂 5.photochemica 光化学的な 6.decomposiion 分角 yproduct: 硬生成物 8. rehing:柄製 9.caiyzed reacton :衣区応 10 ngreacdon : 折反計 1. cmrbonmonoridei 一誠化素 12.cataibet i角 。 15. synhess gms :全成ガス 14. shift reacton : シフト反応

未解決 回答数: 1