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質問の種類

英語 中学生

答えがないので合っているか採点して欲しいです🙇🏻‍♀️

1. 以下の英文を読んで, Questionsに英語で答えなさい。 Tom is a middle school student living in Tokyo, Japan. He loves soccer very much. He plays soccer at his school's club. Every day, after school, he goes to the soccer field to practice for two hours. He thinks that if he practices a lot, he can become very good. So, he practices every day, even if it is raining or snowing. On weekends, Tom plays soccer with his friends at a park near his house. They make teams and play games. Tom thinks this is very fun. He likes to play with his friends and he likes to win the games. Tom's dream is to become a professional soccer player. He likes Lionel Messi, a famous soccer player. Tom wants to be as good as Messi. He works hard every day to become better at soccer. Tom also likes to watch soccer games on TV. He often watches games with his father. They like the same teams. They talk about the games and the players. Tom thinks that watching games helps him learn how to be a better player. Tom is busy with soccer, but he also studies hard. He knows that school is important. He always does his homework and studies for tests. He is good at English and likes to learn new words. He thinks that English will be useful when he is a professional soccer player. Tom's life is all about soccer, but he is not just a soccer player. He is a good student, a good friend, and he has big dreams. He thinks that if he works hard, he can make his dreams come true.

解決済み 回答数: 1
数学 高校生

画像の赤線の部分で、lに代入した-1、mに代入した-3がどこから来たのかわからないので教えていただきたいです!

Example 40 ★★★★★ 2つの実数, gがある。 を初項, g を公差とする等差数列を (an を初 公差とする等差数列を {bm} とする。 いま数列{an) の第2項が a2=8 であり, 数列 {bm} の第4項がbx=14 であるとする。 このとき、 {bm に共通して現れる数を小さい順に並べて新しい等差数列 {c} を作ると、 の値は,g=1である。 また,このとき2つの数列 (am)と cmの初項は,公差はである。 また {c} の初項から第n項ま での和は,nの式で表すと 解答 an=p+(n-1)g, bm=g+(n-1)p である。 [類 13 関西学院大 ] a2=8 から p+g=8 ① b=14 から 3p+g=14 ② ①,② を解いて よって カ=3, g=15 答 an=3+5(n-1)=5n-2 bn=5+3(n-1)=3n+2 共通な項を α = bm とすると 5l-2=3m+2 また ③ ④ から 5・(−1)-2=3・(-3)+2_ 5(+1)=3(m+3) 5と3は互いに素であるから よって l=3k-1 (k≧1) したがって l+1=3k(kは整数) Cn=a3n-1=5(3n-1)-2=15n-7 ゆえに, 数列 {c} は初項 78, 公差 15 の等差数列である。 答 よって, 数列 {c}の初項から第n項までの和は 1/2n(cs+cm)=1/2n{8+(15n-7))=1/12n(15n+1) (答) [Key a=bm を満たす を求める。 Key 等差数列の和 等差数列{a} の初項か ら第n項までの和 Sn は Sn = 1/2₂n (artan)

解決済み 回答数: 1