fini= 141-21
n²-n+=
をすべて求めよ
整数になるような軽いの値
fino 12.023 - f(u) =)
-->>
141-21
n²n+2
-21, 140-2| = n²n+2
(TEL n²n+2 = (n-1) ²+ ½ > 0)
(7) `nza; 41-2 = n²n+2
n² sn + 4 = 0, (n-1)(n-4) ≤0, 1≤n≤4
れは整数だからn=1,2,3,4
f(₁) =====1, f(a) = f(3) = 7
f(4)=1/4=1 よって
n=1₁4
(1) n≤o art, ~4n+2=n²n+2
n²+3no, n(n+3) ≤ 0, -35450²
んは整数だからn=①,2,3
f(0)=1/12/2=14(H)=f(x2)=1/2
f(-3) = -14 = 1 F₁z n = 0₁-1
24
(ア)(イ)より n=3,0,1,4