[64]
B
2
X
5-20
5
3-x
C.
①
6
5
No.
Date
円円とAB,CAと接する点をF,Gとする
(1) CDをxとおく
CG =
=00=X
AG=AF=5-X
BD = BF = 3-x
よって
AB AF+BF
6 = (5-x) + (3-2)
x=1
CD = 1
#
(2)∠Aの二等分線とBCの交点がEなので
2
①AB: AC = BE: EC ② CA: CE = AI IE
€6:5
6EC=5BE
ECS
ED/C
GBE
3
EC-BC
5
//
5×3
ED
ED
B
ED
C
AIED = 11771ABC
DIED ABC FIL
AIEDABL=2:77
=
15
//
1
EC-CD
15
/
4
//
15
= 5 =
=5515
+1113
AACE = SABC
71
A CIE=AACE
AIED=
14
=
15
ACZE
I
11
MACIE
QIY CLEA LEO
4'
3
@HAZED = LACE
14
#ALED = A ACE
Oft's
41 SATED = FOA BC