Mathematics
Senior High

∫1~√eまでのx分のlogxdx
この定積分の計算をお願いします

Answers

logx=tと置換すると、dx・1/x=dt

∫(0→1/2) (t/x × xdt)
=∫(0→1/2) (tdt)
=[1/2 t^2](0→1/2)
=1/8

こんな感じです。

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