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異なる2つの負の解

(i)異なる2つの実数解
(ii)軸が負
(iii)f(0)が正になる(下に凸のとき)

(i)D/4=m²-(2m+3)=(m-3)(m+1)>0
m<-1, 3<m
(ii)平方完成
f(x)=(x+m)²-m²+2m+3
軸x=-m
-m<0
m>0
(iii)f(0)=2m+3>0
m>-3/2
(i)(ii)(iii)の共通範囲を求め、
m>3.

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