✨ Best Answer ✨
折ってできた図形なので△PEQ≡△PCQ
よって ∠PEQ=90°
∠QED=180-(70+90)=20°
ABCDは長方形なので∠EDQ=90°
三角形の内角の和は180°なので
∠DQE=180-(20+90)=70°
∠EQC=180-70=110°
∠EQP=∠CQPなので ∠EQP=110÷2=55°
Answers
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉
Recommended
【中2数学】平行四辺形
364
16
【基礎】図形の定義・定理
78
19
ありがとうございます！