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展開すると、sin^2θ+cos^2θ+2cosθsinθ+sin^2θ+cos^2θ−2sinθcosθとなり、sin^2θ+cos^2θ=1なので、答えは2です。
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✨ Best Answer ✨
展開すると、sin^2θ+cos^2θ+2cosθsinθ+sin^2θ+cos^2θ−2sinθcosθとなり、sin^2θ+cos^2θ=1なので、答えは2です。
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