-sinπ/12+√3cosπ/12
=2(-1/2sinπ/12+√3/2cosπ/12)
=2(cos2/3πsinπ/12+sin2/3πcosπ/12)
=2sin(π/12+2/3π)
=2sin3/4π
=√2
どうでしょうか.
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