Mathematics
Senior High
a³＋b³＋c³の部分の計算の仕方を教えて欲しいです🙇🏻♀️
(3) (a+b+c)=α°+6°+c+2(ab+bc+ca)より
1
ab+bc+ca=→ (at+6+c)?-(α?+68+c))3Dー)
よって
a°++c°=(a+b+c)°-3(a+6+c)(ab+bc+ca)+3abc
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