1問目
初項1、公比1/3の等比数列の第n項までの和S_nは、
S_n=(3/2)×{1−(1/3)^n}
よって、lim[n→∞]S_n=3/2
2問目
lim[x→2]{√(2x+5)+3}/2{√(x+2)+2}
=3/4
Answers
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉
1問目
初項1、公比1/3の等比数列の第n項までの和S_nは、
S_n=(3/2)×{1−(1/3)^n}
よって、lim[n→∞]S_n=3/2
2問目
lim[x→2]{√(2x+5)+3}/2{√(x+2)+2}
=3/4
Users viewing this question
are also looking at these questions 😉
ありがとうございます