Mathematics
Senior High
これって一番下の答えのようにマイナスをくくり出さなくてはいけませんかね?!
33
aについて整理すると
bc(b-c)+ca(c-a)+ab(a-b)
= bc(b-c)+c°a-ca'+α'b-ab
= (6-c)a- (がーC)a+bc(6-c)
= (6-c)a-(6-c)(b+c)a+bc(b-c)
= (6-c){a- (6+c)a+bc}
= (6-c)(aーb)(aーc))
=ー(a-b)(b-c)(e-a)
ーa)+ab(a-b)
Answers
Were you able to resolve your confusion?
Users viewing this question
are also looking at these questions 😉