Mathematics
Undergraduate
y'=(2t(y^3+1))/(3y^2)の一般解は画像の答えで合っていますか?
dy. 2t12+1)_
dt
P1 4=12t de
\tetl
Rogltetlte'=ttc!
Raa.l?=t+c-C"
lez HリにピャC'(ビ-C!-c')
Y41 =tpt+C'
P+=cet (C=te)
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