Mathematics
Senior High
Resolved
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問11 次の三角比を鋭角の三角比で表せ。
(1) sin155°
(2) cos144°
(3) tan172°円
(4) sin105"
Dp112
Cos t 9o -Sih.
Sint90- CoS
() Sin 115°
- Sih (186°-6は)
Sin 65°
(2) Cosll4
= Cos (l80- b6)
ニ- cos66°
Sin
CS
Cos
(3) tanl72°
- tan 1188-8)
tan go
14) S'hla5°
- Sin (98+ 150)
- COSI5°
Sih logo
- Sin (l00-ns)
; Sin n5°
どらら7もo?
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