Mathematics
Senior High
f(x)=a(x+k)(x-3k)のグラフの、x軸との交点のx座標は、3k,-kなのですが、求め方・途中式はこれで合っていますか?
fx) - a(xtk) (2-3非)
へ
fix) = 0 とすると.
0-a(x+k)(スー3k)
0- (xtk)(x-3k)
X= 張.-k
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