Mathematics
Senior High
Solved
この問題で、∠BADが30°＋αになる理由を教えてください！
B
EX100°
F
30°
00
D
(3) △AFDにおいて
ZBAD= ZAFD+ZADF=30° +α
ACに対する円周角は等しいから
ZABC= ZADC=a
図
ABAE において
ZBED= ZBAE+ZABE
=(30°+α)+α=2α+30°
DECに。
ゆえに
2a+ 30°= 100°
よって
α=35°
No.
30°円8L
f<300
ED(00 0
C
AA
Answers
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ありがとうございます！！