✨ Best Answer ✨
↓こんな感じになりました!!
x³+ax²ーx²-a
=x²(xー1)+a(x²ー1)
=x²(xー1)+a(x+1)(x-1)
=(xー1)(x²+ax+a)
✨ Best Answer ✨
↓こんな感じになりました!!
x³+ax²ーx²-a
=x²(xー1)+a(x²ー1)
=x²(xー1)+a(x+1)(x-1)
=(xー1)(x²+ax+a)
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