Mathematics
Senior High
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なぜ25になるのですか?
3
点A(-3, 4) からの距離が5であるx軸上の点Bの座標を求めよ。
8
つく軸上の点を(x,0)とおく
B
AB=5 31
√√³x = (-3) ² ² + (0-4)³² = 5
(X+3)² + (4)
(25)
2²+ 6x
= 0
X(X+6)=0
x = 0₁-6
よって点Bの座標は (0.0)または (-6.0)
m
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