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単位円を書けば、0≦θ<2πのとき、θ＝π/6,(5/6)πです。今回の場合、θの範囲が未知なので、
θ＝(π/6)+2nπ,(5/6)π+2nπ (n∈ℤ)となります。
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✨ Best Answer ✨
単位円を書けば、0≦θ<2πのとき、θ＝π/6,(5/6)πです。今回の場合、θの範囲が未知なので、
θ＝(π/6)+2nπ,(5/6)π+2nπ (n∈ℤ)となります。
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are also looking at these questions 😉
ありがとうございます✨