Mathematics
Junior High
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(7) axb+c=ab+c
(10) (x+5) 2
x +5
2
(12) (4×a+2) × 3
= 12a + 6
(14) (axb+cx d) x 2
= 2ab + 2 cd
(16) 3÷(a+b)
3
atb
1
(18) 5xxxx-4xx
= 5x² - 4x
2
x x²(a + b)
(20) 2÷xx(a+b)
2a + 2b
x
(8) x-3×y=-x-3y (9) axa-a÷4
=a²-a
(11) nx(-3)-axm
= -3n-ami
3xx-4
(13) (xx3-y) × m
= 3mtc - my
3/2
+
(15) (a÷4+c÷2) × a
=
(17) a÷(a-2)
a
a-2
=
4
= a² + === ac
4
2
11
4
(19) (-3)xa÷b_a
= − 3a + b-a
3g -a
b
-3a+ab
b
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答えは
3a+ab
- ───── でいいんですか?
b
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