Mathematics
Senior High
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詳しく教えていただきたいです🙇♀️
1枚目が問題、2枚目が解答です。
10=1のとき, cos と tane の値を求めよ。
3
26090°180° とする。 sin0=
260
cos²0=1-sin²0
1\2
-1-(-/-)²
=1
3
60/00
90° ≦ 0 ≦180°のとき
IS -1
y↑
1
MO
1
3
1x
70-4 STEP I
261
cos ≦0 であるから
cose
8
9
F
tan 0 =
.
(
sin
COS
5
1
2√2
2√/2
3
2√2
- 1/2 + (-²²)
÷
3
√2
4
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理解できました。表もありがとうございます!